高等数学常用公式

发表于 2023-04-14 分类于数学，微积分阅读次数：本文字数： 2.3k 阅读时长 ≈ 9 分钟

1. 常见等价无穷小

$\sin x \sim x$	$\tan x \sim x$	$\arcsin x \sim x$
$\arctan x \sim x$	$\displaystyle\left( 1 - \cos x \right) \sim \frac{x^2}{2}$	$\ln (1+x) \sim x$
$\left( e^x -1 \right) \sim x$	$\left( a^x - 1 \right) \sim x \ln a$	$\left( \left( 1+x \right) ^\alpha -1 \right) \sim \alpha x$

2. 导数基本公式

一般函数	三角函数	反三角函数	双曲函数 (圆函数)
$\left( C \right)' = 0$	$\left( \sin x \right)' = \cos x$	$\displaystyle\left( \arcsin x \right)' = \frac{1}{\sqrt{1-x^2}}$	$\displaystyle\left( \sinh x \right)' = \left(\frac{e^x-e^{-x}}{2}\right)' = \cosh x$
$\left( x^\alpha \right)'=\alpha x^{\alpha-1} \left( \alpha \in \mathbf{Z} \right)$	$\left( \cos x \right)' = -\sin x$	$\displaystyle\left( \arccos x \right)' = -\frac{1}{\sqrt{1-x^2}}$	$\displaystyle\left( \cosh x \right)' = \left( \frac{e^x+e^{-x}}{2} \right)'=\sinh x$
$\displaystyle\left( \log_ax\right)'=\frac{1}{x\ln a}$	$\displaystyle\left( \tan x \right)' = \frac{1}{\cos^2 x}=\sec^2 x$	$\displaystyle\left( \arctan x \right)' = \frac{1}{1+x^2}$	$\displaystyle\left( \mathrm{arsinh} \, x \right)' = \left(\ln \left( x+\sqrt{x^2 + 1} \right) \right)' = \frac{1}{x^2+1}$
$( \ln$\| $x$ \|$)'=\displaystyle\frac{1}{x}$	$\displaystyle\left( \cot x \right)' = -\frac{1}{\sin^2 x} = -\csc^2 x$	$\displaystyle\left( \mathrm{arccot} \, x \right)' = -\frac{1}{1+x^2}$	$\displaystyle\left( \mathrm{arcosh} \, x \right)' = \left( \ln \left( x + \sqrt{x^2 - 1} \right) \right)' = \frac{1}{\sqrt{x^2-1}}$
	$\left( \sec x \right)' = \sec x \cdot \tan x$
	$\left( \csc x \right)' = \csc x \cdot \cot x$

Newton-Leibniz 公式：
\[ \begin{aligned} \left( u \cdot v \right)^{\left( n \right)} &= u^{\left( n \right)}v + nu^{\left( n-1 \right)}v' + \frac{n \left( n-1 \right)}{2!}u^{\left( n-2 \right)}v'' + \cdots + \frac{n\left( n-1 \right)\cdots\left(n-k+1\right)}{k!}u^{\left( n-k \right)}v^{(k)} + \cdots + uv^{\left( n \right)} \\ &= \sum_{k=0}^{n}C_n^k u^{\left( u-k \right)}v^k \end{aligned} \]
可以注意到 Newton-Leibniz 公式具有类似二项式定理展开的形式。

3. 几个初等函数的 Maclaurin 公式

3.1 Taylor 公式的一般形式

\[ f(x)=f(x_0) + f'(x_0)(x-x_0) + \frac{f''(x_0)}{2!}(x-x_0)^2 + \cdots + \frac{f^{(n)}(x_0)}{n!}(x-x_0)^n + R_n \]

其中

\[ R_n = \frac{f^{(n+1)}(\xi)}{(n+1)!}(x-x_0)^{n+1} \, (\xi\,在\,x\,和\,x_0\,之间) = o\left( \left( x - x_0 \right)^n \right)(x\to x_0) \]

3.2 Maclaurin 公式的一般形式

\[ f(x)=f(0)+f'(0)\,x + \frac{f''(0)}{2!}x^2 + \cdots + \frac{f^{(n)}(0)}{n!}x^n + R_n \]

其中

\[ R_n = \frac{f^{(n+1)}(\xi)}{(n+1)!}x^{n+1} \, (\xi\,在\,0\,和\,x\,之间) = \frac{f^{(n+1)}(\theta x)}{(n+1)!} x^{n+1}(0<\theta<1) = o\left( \left( x - x_0 \right)^n \right)(x\to x_0) \]

3.3 指数函数的 Maclaurin 展开式

\[ e^x=1+x+\frac{x^2}{2} + \frac{x^3}{3} + \cdots +\frac{x^n}{n!} + \frac{e^{\theta x}}{(n+1)!}(0<\theta<1) \]

3.4 正弦函数的 Maclaurin 展开式

\[ \sin x = x - \frac{x^3}{3!} + \frac{x^5}{5!} + \cdots + (-1)^{m-1}\frac{x^{2m-1}}{(2m-1)!} + R_{2m} \]

其中

\[ R_{2m}=\frac{\sin\left( \theta x + \frac{(2m-1)\pi}{2}\right)}{(2m+1)!}x^{2m+1} = o(x^{2m})(0<\theta <1) \]

3.5 余弦函数的 Maclaurin 展开式

\[ \cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} + \cdots + (-1)^m\frac{x^{2m}}{2m!} + R_{2m+1} \]

其中

\[ R_{2m+1}=\frac{\cos(\theta x + (m+1)\pi)}{(2m+2)!} x^{2m+2}=o(x^{2m+2}) (0<\theta <1) \]

3.6 $\ln (1+x)$ 的 Maclaurin 展开式

\[ \ln(1+x) = x - \frac{x^2}{2} + \frac{x^3}{3} -\frac{x^4}{4} + \cdots + \frac{(-1)^{n-1}x^n}{n} + R_n(x) \]

其中

\[ R_n(x) = \frac{(-1)^n}{(n+1)(1+\theta x)^{n+1}}x^{n+1} = o(x^n)(0<\theta <1) \]

3.7 $(1+x)^\alpha$ 的 Maclaurin 展开式

\[ (1+x)^\alpha = 1 + \alpha x + \frac{\alpha(\alpha-1)}{2!}x^2 + \cdots + \frac{\alpha(\alpha - 1)\cdots (\alpha-n+1)}{n!}x^n + R_n(x) \]

其中

\[ R_n(x) = \frac{\alpha(\alpha -1)\cdots(\alpha-n)}{(n+1)!}(1+\theta x)^{\alpha-n-1}x^{n+1} = o(x)(0<\theta <1) \]

3.8 $\frac{1}{1-x}$ 的 Maclaurin 展开式

\[ \frac{1}{1-x} = 1+x+x^2+\cdots+x^n +o(x^n) \]

4. 曲率及曲率半径

曲率	曲率半径
$K=\left\\| \dfrac{\mathrm{d}\alpha}{\mathrm{d}s}\right\\| \xlongequal{\tan \alpha = y' \Rightarrow \alpha = \arctan y'} \dfrac{\left\\| \frac{y''}{1+y'^2}\mathrm{d}x \right\\|}{\sqrt{1+y'^2}}\mathrm{d}x = \dfrac{\left\\| y'' \right\\|}{\left( 1 + y' \right)^\frac{3}{2}}$	$R = \frac{1}{K}$

5. 积分常用公式

序	描述	公式
1	定积分的定义	$\displaystyle\int^1_0f(x)\mathrm{d}x=I=\lim_{\lambda \to 0}\sum_{i=1}^{n}f(\xi_i)\Delta x_i$，其中 $\lambda = \max \left\{ \Delta x_1,\Delta x_2, \cdots, \Delta x_n \right\}$
2	变上限积分	$考察定积分\displaystyle\int^x_af(x)\mathrm{d}x=\int^x_af(t)\mathrm{d}t$，对 $\displaystyle\Phi(x)=\int_a^xf(t)\mathrm{d}t$，有 $\displaystyle\Phi'(x)=\frac{\mathrm{d}}{\mathrm{d}x}\int_a^xf(t)\mathrm{d}t = f(x)$
3.	—	$\displaystyle\frac{\mathrm{d}}{\mathrm{d}x}\int^{\beta(x)}_{\alpha(x)}f'(t)\mathrm{d}t = f\left[ \beta\left(x\right)\right]\beta'(x)-f[\alpha(x)]\alpha'(x)$
4	上下限对称的积分	若 $f(x)$ 为偶函数，则 $\displaystyle\int_{-a}^af(x)\mathrm{d}x=2\int_0^af(x)\mathrm{d}x$；若 $f(x)$ 为奇函数，则 $\displaystyle\int_{-a}^af(x)\mathrm{d}x=0$
5	周期函数的积分	$\displaystyle f(x+T)=f(x)\Rightarrow\int_0^{nT}f(x)\mathrm{d}x=n\int^T_0f(x)\mathrm{d}x$
6	分部积分法	$\displaystyle\int uv'\mathrm{d}x=uv - \int u'v\mathrm{d}x \Leftrightarrow \int u\mathrm{d}v = uv - \int v\mathrm{d}u$

6. 基本积分表

序	积分式
1	$\displaystyle\int k\mathrm{d}x=kx+C$，特别地 $\displaystyle\int\mathrm{d}x=x+C$
2	$\displaystyle\int x^\mu\mathrm{d}x=\frac{x^{\mu+1}}{\mu+1}+C(\mu\ne-1)$，特别地 $\displaystyle\int \frac{\mathrm{d}x}{x^2}=-\frac{1}{x}+C,\int\frac{\mathrm{d}x}{\sqrt{x}}=2\sqrt{x}+C$
3	$\displaystyle\int\frac{\mathrm{d}x}{x}=\ln \\|x\\|+C$
4	$\displaystyle\int\frac{\mathrm{d}x}{1+x^2} = \arctan x +C$
5	$\displaystyle\int\frac{\mathrm{d}x}{\sqrt{1-x^2}}=\arcsin x+C$
6	$\displaystyle\int\sin x\mathrm{d}x = -\cos x+C, \int\cos x\mathrm{d}x = \sin x +C$
7	$\displaystyle\int\frac{\mathrm{d}x}{\cos^2x} = \int\sec^2x\mathrm{d}x = \tan x +C, \int\frac{\mathrm{d}x}{\sin^2x}=\int\csc^2x\mathrm{d}x = -\cot x +C$
8	$\displaystyle\int a^x\mathrm{d}x = \frac{a^x}{\ln a} + C$，特别地 $\displaystyle\int e^x\mathrm{d}x = e^x +C$
9	$\displaystyle\int \sinh x\mathrm{d}x = \cosh x + C，\int \cosh x \mathrm{d}x=\sinh x +C$

7. 三角函数相关公式

序	公式
1	$\sin^2x+\cos^2x=1, \tan^2x+1=\sec^2x,\cot^2x+1=\csc^2x$
2	$\begin{aligned}&\cosh^2x-\sinh^2x=1,\\ &\sinh(x\pm y)=\sinh x\cdot\cosh y \pm \sinh y\cdot\cosh x, \cosh(x\pm y) = \cosh x\cdot\cosh y,\\ &\sinh2x = 2\sinh x\cdot \cosh x, \cosh 2x = \cosh^2x+\sinh^2x = 2\cosh^2x - 1\end{aligned}$
3 积化和差公式	$\sin\alpha\cos\beta=\frac12[\sin(\alpha+\beta)+\sin(\alpha-\beta)],\cos\alpha\sin\beta = \frac12[\sin(\alpha+\beta) - \sin(\alpha-\beta)]$ $\cos\alpha\cos\beta = \frac12[cos(\alpha+\beta) + cos(\alpha - \beta)], \sin\alpha\sin\beta=-\frac12[\cos(\alpha+\beta) - \cos(\alpha-\beta)]$
4 和差化积公式	$\displaystyle\sin\alpha + \sin\beta = 2\sin\left(\frac{\alpha+\beta}{2}\right) \cos\left(\frac{\alpha-\beta}{2}\right), \sin\alpha - \sin\beta = 2\sin\left(\frac{\alpha-\beta}{2}\right) \cos\left(\frac{\alpha+\beta}{2}\right)$ $\displaystyle\cos\alpha + \cos\beta = 2\cos\left(\frac{\alpha+\beta}{2}\right) \cos\left(\frac{\alpha-\beta}{2}\right), \cos\alpha - \cos\beta = -2\sin\left(\frac{\alpha+\beta}{2}\right) \sin\left(\frac{\alpha-\beta}{2}\right)$
5 三角代换	$\displaystyle\sqrt{a^2-x^2}\xrightarrow{x=a\sin t}a\cos t, \sqrt{a^2+x^2} \xrightarrow{x=a\tan t}a\sec t, \sqrt{x^2-a^2}\xrightarrow{x=a\sec t}a\tan t \left( a>0,t\in\left( -\frac{\pi}{2} , \frac{\pi}{2} \right) \right)$
6	$\displaystyle\int\sqrt{a^2-x^2}\mathrm{d}x = \frac{a^2}{2}\arcsin\frac xa + \frac12x\sqrt{a^2-x^2} + C(a>0)$
7	$\displaystyle\int\sqrt{x^2+a^2}\mathrm{d}x = \frac x2\sqrt{x^2+a^2} + \frac{a^2}2\ln \left\\| x+\sqrt{x^2+a^2} \right\\|+C(a>0)$
8	$\displaystyle\int\frac{1}{\sqrt{x^2+a^2}}\mathrm{d}x = \ln\left\\| x+ \sqrt{x^2+a^2} \right\\| +C$, $\displaystyle\int\frac{1}{\sqrt{x^2-a^2}}\mathrm{d}x = \ln\left\\| x + \sqrt{x^2+a^2}\right\\|(a>0)$，特别地，$\displaystyle\int\frac{1}{\sqrt{x^2+1}}\mathrm{d}x=\left(x+\sqrt{x^2+1}\right) = \mathrm{arsinh}\, x$, $\displaystyle\int\frac{1}{\sqrt{x^2-1}}\mathrm{d}x = \ln\left( x+\sqrt{x^2-1}\right) = \mathrm{arcosh}\, x$
9	$\displaystyle\int\sec x\mathrm{d}x = \int\frac{1}{\cos x}\mathrm{d}x = \int\frac{\sec^2x+\sec x \tan x}{\sec x + \tan x}\mathrm{d}x = \int\frac{1}{\sec x + \tan x}\mathrm{d}(\sec x + \tan x) = \ln \left\\| \sec x + \tan x \right\\| + C$
10	$\displaystyle\int\csc x\mathrm{d}x = \int\frac{1}{\sin x}\mathrm{d}x = \ln\left\\| \tan\frac x2 \right\\| + C = \frac 12 \ln \left\\| \frac{1-\cos x}{1 + \cos x}\right\\| + C$
11	$\displaystyle\int\tan x\mathrm{d}x = \int\frac{\sin x}{\cos x}\mathrm{d}x = -\int\frac{1}{\cos x}\mathrm{d}(\cos x) = -\ln \left\\| \cos x\right\\| +C$
12	$\displaystyle\int\frac{1}{\tan x}\mathrm{d}x = \int\frac{\cos x}{\sin x}\mathrm{d}x = \int\frac{1}{\sin x}\mathrm{d}(\sin x) = \ln\left\\| \sin x \right\\| + C$
13	$\displaystyle\int\arctan x\mathrm{d}x = x\arctan x - \ln \left\\| 1+x^2 \right\\| +C$
14 Wallis 公式	$\displaystyle\int^{\frac{\pi}{2}}_{0}\sin^nx\mathrm{d}x = \int^{\frac{\pi}{2}}_{0}\cos^nx\mathrm{d}x = \begin{cases} \displaystyle\frac{n-1}{n}\cdot\frac{n-3}{n-2}\cdot\cdots\cdot\frac12\cdot\frac\pi2,&n为偶数 \\ \displaystyle\frac{n-1}{n}\cdot\frac{n-3}{n-2}\cdot\cdots\cdot\frac23\cdot1,&n为奇数 \end{cases} \\ = \begin{cases} \displaystyle\frac{(n-1)!!}{n!!}\cdot\frac\pi2,&n为偶数 \\ \displaystyle\frac{(n-1)!!}{n!!},&n为奇数 \end{cases}$
15	$\displaystyle\int_0^\pi\sin^nx\mathrm{d}x = 2\int^\frac\pi2_0\sin^nx\mathrm{d}x,\int_0^\pi\cos^nx\mathrm{d}x = \begin{cases} 2\displaystyle\int^\frac\pi2_0\cos^nx\mathrm{d}x,&n为偶数 \\ 0,&n为奇数 \end{cases}$ $\displaystyle\int_0^{2\pi}\sin^nx = \int_0^{2\pi}\cos^nx\mathrm{d}x = \begin{cases} 4\displaystyle\int^\frac\pi2_0\sin^nx\mathrm{d}x,&n为偶数 \\ 0,&n为奇数 \end{cases}$ $\displaystyle\int_0^\frac\pi2f(\sin x)\mathrm{d}x = \int_0^\frac\pi2f(\cos x)\mathrm{d}x$, $\displaystyle\int_0^\pi f(\sin x)\mathrm{d}x \ne \int_0^\pi f(\cos x)\mathrm{d}x$ $\displaystyle\int_0^\pi\pi f(\sin x)\mathrm{d}x = \frac\pi2\int_0^\pi f(\sin x)\mathrm{d}x = \pi\int_0^\frac\pi2 f(\sin x)\mathrm{d}x$
16 万能公式	令 $u=\displaystyle\tan\frac x2,x=2\arctan u$，则 $\displaystyle\sin x = \frac{2u}{1+u^2},\cos x=\frac{1-u^2}{1+u^2}, \mathrm{d}x = \frac{2}{1+u^2}\mathrm{d}u$
17	$\displaystyle\int \frac{a\cos x+ b\sin x}{c\cos x + d \sin x} = A\int\mathrm{d}x+B\int\frac{\mathrm{d}(c\cos x+d \sin x)}{c \cos x + d \sin x}$ (设 $a\cos x + b\sin x = A(c \cos x + d \sin x) + B(c \cos x + d \sin x)'$，由待定系数法求出A、B)$

\(\sin x \sim x\)	\(\tan x \sim x\)	\(\arcsin x \sim x\)
\(\arctan x \sim x\)	\(\displaystyle\left( 1 - \cos x \right) \sim \frac{x^2}{2}\)	\(\ln (1+x) \sim x\)
\(\left( e^x -1 \right) \sim x\)	\(\left( a^x - 1 \right) \sim x \ln a\)	\(\left( \left( 1+x \right) ^\alpha -1 \right) \sim \alpha x\)

一般函数	三角函数	反三角函数	双曲函数 (圆函数)
\(\left( C \right)' = 0\)	\(\left( \sin x \right)' = \cos x\)	\(\displaystyle\left( \arcsin x \right)' = \frac{1}{\sqrt{1-x^2}}\)	\(\displaystyle\left( \sinh x \right)' = \left(\frac{e^x-e^{-x}}{2}\right)' = \cosh x\)
\(\left( x^\alpha \right)'=\alpha x^{\alpha-1} \left( \alpha \in \mathbf{Z} \right)\)	\(\left( \cos x \right)' = -\sin x\)	\(\displaystyle\left( \arccos x \right)' = -\frac{1}{\sqrt{1-x^2}}\)	\(\displaystyle\left( \cosh x \right)' = \left( \frac{e^x+e^{-x}}{2} \right)'=\sinh x\)
\(\displaystyle\left( \log_ax\right)'=\frac{1}{x\ln a}\)	\(\displaystyle\left( \tan x \right)' = \frac{1}{\cos^2 x}=\sec^2 x\)	\(\displaystyle\left( \arctan x \right)' = \frac{1}{1+x^2}\)	\(\displaystyle\left( \mathrm{arsinh} \, x \right)' = \left(\ln \left( x+\sqrt{x^2 + 1} \right) \right)' = \frac{1}{x^2+1}\)
\(( \ln\)\| \(x\) \|\()'=\displaystyle\frac{1}{x}\)	\(\displaystyle\left( \cot x \right)' = -\frac{1}{\sin^2 x} = -\csc^2 x\)	\(\displaystyle\left( \mathrm{arccot} \, x \right)' = -\frac{1}{1+x^2}\)	\(\displaystyle\left( \mathrm{arcosh} \, x \right)' = \left( \ln \left( x + \sqrt{x^2 - 1} \right) \right)' = \frac{1}{\sqrt{x^2-1}}\)
	\(\left( \sec x \right)' = \sec x \cdot \tan x\)
	\(\left( \csc x \right)' = \csc x \cdot \cot x\)

序	积分式
1	\(\displaystyle\int k\mathrm{d}x=kx+C\)，特别地 \(\displaystyle\int\mathrm{d}x=x+C\)
2	\(\displaystyle\int x^\mu\mathrm{d}x=\frac{x^{\mu+1}}{\mu+1}+C(\mu\ne-1)\)，特别地 \(\displaystyle\int \frac{\mathrm{d}x}{x^2}=-\frac{1}{x}+C,\int\frac{\mathrm{d}x}{\sqrt{x}}=2\sqrt{x}+C\)
3	\(\displaystyle\int\frac{\mathrm{d}x}{x}=\ln \\|x\\|+C\)
4	\(\displaystyle\int\frac{\mathrm{d}x}{1+x^2} = \arctan x +C\)
5	\(\displaystyle\int\frac{\mathrm{d}x}{\sqrt{1-x^2}}=\arcsin x+C\)
6	\(\displaystyle\int\sin x\mathrm{d}x = -\cos x+C, \int\cos x\mathrm{d}x = \sin x +C\)
7	\(\displaystyle\int\frac{\mathrm{d}x}{\cos^2x} = \int\sec^2x\mathrm{d}x = \tan x +C, \int\frac{\mathrm{d}x}{\sin^2x}=\int\csc^2x\mathrm{d}x = -\cot x +C\)
8	\(\displaystyle\int a^x\mathrm{d}x = \frac{a^x}{\ln a} + C\)，特别地 \(\displaystyle\int e^x\mathrm{d}x = e^x +C\)
9	\(\displaystyle\int \sinh x\mathrm{d}x = \cosh x + C，\int \cosh x \mathrm{d}x=\sinh x +C\)

序	公式
1	\(\sin^2x+\cos^2x=1, \tan^2x+1=\sec^2x,\cot^2x+1=\csc^2x\)
2	\(\begin{aligned}&\cosh^2x-\sinh^2x=1,\\ &\sinh(x\pm y)=\sinh x\cdot\cosh y \pm \sinh y\cdot\cosh x, \cosh(x\pm y) = \cosh x\cdot\cosh y,\\ &\sinh2x = 2\sinh x\cdot \cosh x, \cosh 2x = \cosh^2x+\sinh^2x = 2\cosh^2x - 1\end{aligned}\)
3 积化和差公式	\(\sin\alpha\cos\beta=\frac12[\sin(\alpha+\beta)+\sin(\alpha-\beta)],\cos\alpha\sin\beta = \frac12[\sin(\alpha+\beta) - \sin(\alpha-\beta)]\) \(\cos\alpha\cos\beta = \frac12[cos(\alpha+\beta) + cos(\alpha - \beta)], \sin\alpha\sin\beta=-\frac12[\cos(\alpha+\beta) - \cos(\alpha-\beta)]\)
4 和差化积公式	\(\displaystyle\sin\alpha + \sin\beta = 2\sin\left(\frac{\alpha+\beta}{2}\right) \cos\left(\frac{\alpha-\beta}{2}\right), \sin\alpha - \sin\beta = 2\sin\left(\frac{\alpha-\beta}{2}\right) \cos\left(\frac{\alpha+\beta}{2}\right)\) \(\displaystyle\cos\alpha + \cos\beta = 2\cos\left(\frac{\alpha+\beta}{2}\right) \cos\left(\frac{\alpha-\beta}{2}\right), \cos\alpha - \cos\beta = -2\sin\left(\frac{\alpha+\beta}{2}\right) \sin\left(\frac{\alpha-\beta}{2}\right)\)
5 三角代换	\(\displaystyle\sqrt{a^2-x^2}\xrightarrow{x=a\sin t}a\cos t, \sqrt{a^2+x^2} \xrightarrow{x=a\tan t}a\sec t, \sqrt{x^2-a^2}\xrightarrow{x=a\sec t}a\tan t \left( a>0,t\in\left( -\frac{\pi}{2} , \frac{\pi}{2} \right) \right)\)
6	\(\displaystyle\int\sqrt{a^2-x^2}\mathrm{d}x = \frac{a^2}{2}\arcsin\frac xa + \frac12x\sqrt{a^2-x^2} + C(a>0)\)
7	\(\displaystyle\int\sqrt{x^2+a^2}\mathrm{d}x = \frac x2\sqrt{x^2+a^2} + \frac{a^2}2\ln \left\\| x+\sqrt{x^2+a^2} \right\\|+C(a>0)\)
8	\(\displaystyle\int\frac{1}{\sqrt{x^2+a^2}}\mathrm{d}x = \ln\left\\| x+ \sqrt{x^2+a^2} \right\\| +C\), \(\displaystyle\int\frac{1}{\sqrt{x^2-a^2}}\mathrm{d}x = \ln\left\\| x + \sqrt{x^2+a^2}\right\\|(a>0)\)，特别地，\(\displaystyle\int\frac{1}{\sqrt{x^2+1}}\mathrm{d}x=\left(x+\sqrt{x^2+1}\right) = \mathrm{arsinh}\, x\), \(\displaystyle\int\frac{1}{\sqrt{x^2-1}}\mathrm{d}x = \ln\left( x+\sqrt{x^2-1}\right) = \mathrm{arcosh}\, x\)
9	\(\displaystyle\int\sec x\mathrm{d}x = \int\frac{1}{\cos x}\mathrm{d}x = \int\frac{\sec^2x+\sec x \tan x}{\sec x + \tan x}\mathrm{d}x = \int\frac{1}{\sec x + \tan x}\mathrm{d}(\sec x + \tan x) = \ln \left\\| \sec x + \tan x \right\\| + C\)
10	\(\displaystyle\int\csc x\mathrm{d}x = \int\frac{1}{\sin x}\mathrm{d}x = \ln\left\\| \tan\frac x2 \right\\| + C = \frac 12 \ln \left\\| \frac{1-\cos x}{1 + \cos x}\right\\| + C\)
11	\(\displaystyle\int\tan x\mathrm{d}x = \int\frac{\sin x}{\cos x}\mathrm{d}x = -\int\frac{1}{\cos x}\mathrm{d}(\cos x) = -\ln \left\\| \cos x\right\\| +C\)
12	\(\displaystyle\int\frac{1}{\tan x}\mathrm{d}x = \int\frac{\cos x}{\sin x}\mathrm{d}x = \int\frac{1}{\sin x}\mathrm{d}(\sin x) = \ln\left\\| \sin x \right\\| + C\)
13	\(\displaystyle\int\arctan x\mathrm{d}x = x\arctan x - \ln \left\\| 1+x^2 \right\\| +C\)
14 Wallis 公式	\(\displaystyle\int^{\frac{\pi}{2}}_{0}\sin^nx\mathrm{d}x = \int^{\frac{\pi}{2}}_{0}\cos^nx\mathrm{d}x = \begin{cases} \displaystyle\frac{n-1}{n}\cdot\frac{n-3}{n-2}\cdot\cdots\cdot\frac12\cdot\frac\pi2,&n为偶数 \\ \displaystyle\frac{n-1}{n}\cdot\frac{n-3}{n-2}\cdot\cdots\cdot\frac23\cdot1,&n为奇数 \end{cases} \\ = \begin{cases} \displaystyle\frac{(n-1)!!}{n!!}\cdot\frac\pi2,&n为偶数 \\ \displaystyle\frac{(n-1)!!}{n!!},&n为奇数 \end{cases}\)
15	\(\displaystyle\int_0^\pi\sin^nx\mathrm{d}x = 2\int^\frac\pi2_0\sin^nx\mathrm{d}x,\int_0^\pi\cos^nx\mathrm{d}x = \begin{cases} 2\displaystyle\int^\frac\pi2_0\cos^nx\mathrm{d}x,&n为偶数 \\ 0,&n为奇数 \end{cases}\) \(\displaystyle\int_0^{2\pi}\sin^nx = \int_0^{2\pi}\cos^nx\mathrm{d}x = \begin{cases} 4\displaystyle\int^\frac\pi2_0\sin^nx\mathrm{d}x,&n为偶数 \\ 0,&n为奇数 \end{cases}\) \(\displaystyle\int_0^\frac\pi2f(\sin x)\mathrm{d}x = \int_0^\frac\pi2f(\cos x)\mathrm{d}x\), \(\displaystyle\int_0^\pi f(\sin x)\mathrm{d}x \ne \int_0^\pi f(\cos x)\mathrm{d}x\) \(\displaystyle\int_0^\pi\pi f(\sin x)\mathrm{d}x = \frac\pi2\int_0^\pi f(\sin x)\mathrm{d}x = \pi\int_0^\frac\pi2 f(\sin x)\mathrm{d}x\)
16 万能公式	令 \(u=\displaystyle\tan\frac x2,x=2\arctan u\)，则 \(\displaystyle\sin x = \frac{2u}{1+u^2},\cos x=\frac{1-u^2}{1+u^2}, \mathrm{d}x = \frac{2}{1+u^2}\mathrm{d}u\)
17	\(\displaystyle\int \frac{a\cos x+ b\sin x}{c\cos x + d \sin x} = A\int\mathrm{d}x+B\int\frac{\mathrm{d}(c\cos x+d \sin x)}{c \cos x + d \sin x}\) (设 \(a\cos x + b\sin x = A(c \cos x + d \sin x) + B(c \cos x + d \sin x)'\)，由待定系数法求出A、B)$